document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=890487>Question 890487</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the sum of two numbers is 50 and their mean proportional is 15, then the numbers are- </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #837954 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=837954\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the sum of two numbers is 50 and their mean proportional is 15, then the numbers are-Let one number be x<BR>\n" );
document.write( "The other number then will be 50-x\r<BR>\n" );
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document.write( "mean proportion is15\r<BR>\n" );
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document.write( "(50-x)/15 = 15/x\r<BR>\n" );
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document.write( "x(50-x) = 225\r<BR>\n" );
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document.write( "50x-x^2=225\r<BR>\n" );
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document.write( "x^2-50x+225=0\r<BR>\n" );
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document.write( "(x-45)(x-5)=0\r<BR>\n" );
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document.write( "5  and 45 are the numbers\r<BR>\n" );
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