document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1139798>Question 1139798</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Maria invests a total of $10,500 in two accounts paying 6% and 15% annual interest, respectively. How much was invested in each account if, after one year, the total interest was $990.00. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #837935 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=837935\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is a solution by a very different method that can be used on any 2-part mixture problem like this.  Especially if the numbers are \"nice\", this method is much faster than the standard algebraic solution method.<br><BR>\n" );
document.write( "$10,500 all invested at 6% would yield $630 interest; all at 15% would yield $1575 interest.  The actual interest amount was $990.<br><BR>\n" );
document.write( "Look at those three interest amounts (on a number line, if it helps) and observe/calculate that $990 is $360/$945 = 72/189 = 8/21 of the way from $630 to $1575.<br><BR>\n" );
document.write( "That means 8/21 of the total was invested at the higher rate.<br><BR>\n" );
document.write( "8/21 of the total $10,500 is 8*$500 = $4000.<br><BR>\n" );
document.write( "ANSWER: $4000 was invested at 15%; the other $6500 at 6%.<br><BR>\n" );
document.write( "CHECK: .15(4000)+.06(6500) = 600+390 = 990<br><BR>\n" );
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