document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1202806>Question 1202806</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is three more than triple the width. If the perimeter is 94 inches, find the dimensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #837933 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=837933\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "A good easy problem for solving using basic algebra....<br><BR>\n" );
document.write( "Let x be the width.<BR>\n" );
document.write( "Then, per the given information, the length is 3x+3. (\"three more than triple the width\")<br><BR>\n" );
document.write( "The perimeter (twice width plus twice length) is 94 inches, so the length plus the width is 94/2 = 47 inches.<br><BR>\n" );
document.write( "Using the expressions for the width and length, write and solve an equation that says length plus width is 47 inches:<br><BR>\n" );
document.write( "(x)+(3x+3) = 47<BR>\n" );
document.write( "4x+3 = 47<BR>\n" );
document.write( "4x = 47-3 = 44<BR>\n" );
document.write( "x = 44/4 = 11<br><BR>\n" );
document.write( "ANSWERS:<BR>\n" );
document.write( "width = x = 11<BR>\n" );
document.write( "length = 3x+3 = 3(11)+3 = 33+3 = 36<br><BR>\n" );
document.write( " </SPAN>\n" );
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