document.write( "Question 1076140: the perimeter of the rectangle if the width is twice the root of the length and the area is 250 \n" ); document.write( "
Algebra.Com's Answer #837932 by josgarithmetic(39617)\"\" \"About 
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\n" ); document.write( "the width is twice the root of the length and the area is 250.
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\n" ); document.write( "\n" ); document.write( "L, length
\n" ); document.write( "2sqrt(L), width
\n" ); document.write( "\"L%2A2sqrt%28L%29=250\"\r
\n" ); document.write( "\n" ); document.write( "\"L%2Asqrt%28L%29=125\"
\n" ); document.write( "\"L%2AL%5E%281%2F2%29=125\"
\n" ); document.write( "\"L%5E%283%2F2%29=5%5E3\"\r
\n" ); document.write( "\n" ); document.write( "\"L%5E%283%2F2%29%2AL%5E%283%2F2%29=5%5E6\"
\n" ); document.write( "\"L%5E3=%285%5E2%29%5E3\"
\n" ); document.write( "\"highlight_green%28L=25%29\"------length\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"Lw=250\"------the given area
\n" ); document.write( "\"25w=250\"
\n" ); document.write( "\"highlight_green%28w=10%29\"------width\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Question asked for perimeter.
\n" ); document.write( "\"2%2A10%2B2%2A25\"
\n" ); document.write( "\"highlight%2870%29\"
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