document.write( "Question 1076140: the perimeter of the rectangle if the width is twice the root of the length and the area is 250 \n" ); document.write( "

Algebra.Com's Answer #837927 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( " $\"highlight%28Find%29\"$ the perimeter of the rectangle if the width is twice the root of the length and the area is 250.
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\n" ); document.write( "\n" ); document.write( "        The answer in the post by @mananth is correct, but on the way he made errors
\n" ); document.write( "        that shocked me. I afraid that they shoked you, too.
\n" ); document.write( "        Therefore, I came to present the solution in a correct form.
\n" ); document.write( "        Read my solution attentively; watch every my step and find the differences between
\n" ); document.write( "        my solution and that by @mananth.\r
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document.write( "Let the length be x.\r\n" );
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document.write( "Then the width = .\r\n" );
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document.write( "Area = 250:   = 250.\r\n" );
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document.write( "Square both sides\r\n" );
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document.write( "    4x^3 = 250*250,\r\n" );
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document.write( "    x^3 = 125*125 =  = ,\r\n" );
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document.write( "    x =  = 25  the length.\r\n" );
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document.write( "    width =  =  = 2*5 = 10.\r\n" );
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document.write( "    the width = 10.\r\n" );
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document.write( "The perimeter = 25 + 10 + 25 + 10 = 70.    ANSWER\r\n" );
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