document.write( "Question 1076140: the perimeter of the rectangle if the width is twice the root of the length and the area is 250 \n" ); document.write( "
Algebra.Com's Answer #837926 by mananth(16946)![]() ![]() You can put this solution on YOUR website! the width is twice the root of the length and the area is 250\r \n" ); document.write( "\n" ); document.write( "length be x \n" ); document.write( "width = \n" ); document.write( "\n" ); document.write( "Area = 250\r \n" ); document.write( "\n" ); document.write( "x*2sqrt(x)=250\r \n" ); document.write( "\n" ); document.write( "square both sides\r \n" ); document.write( "\n" ); document.write( "4x^3= 250*250\r \n" ); document.write( "\n" ); document.write( "x^3= 125*125\r \n" ); document.write( "\n" ); document.write( "x = sqrt(125*125)\r \n" ); document.write( "\n" ); document.write( "x=25 the length \n" ); document.write( "width = 2*sqrt(x)\r \n" ); document.write( "\n" ); document.write( "= 2*sqrt(25) \n" ); document.write( "=10 the width\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |