document.write( "Question 1076140: the perimeter of the rectangle if the width is twice the root of the length and the area is 250 \n" ); document.write( "
Algebra.Com's Answer #837926 by mananth(16946)\"\" \"About 
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the width is twice the root of the length and the area is 250\r
\n" ); document.write( "\n" ); document.write( "length be x
\n" ); document.write( "width = \"2sqrt%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "Area = 250\r
\n" ); document.write( "\n" ); document.write( "x*2sqrt(x)=250\r
\n" ); document.write( "\n" ); document.write( "square both sides\r
\n" ); document.write( "\n" ); document.write( "4x^3= 250*250\r
\n" ); document.write( "\n" ); document.write( "x^3= 125*125\r
\n" ); document.write( "\n" ); document.write( "x = sqrt(125*125)\r
\n" ); document.write( "\n" ); document.write( "x=25 the length
\n" ); document.write( "width = 2*sqrt(x)\r
\n" ); document.write( "\n" ); document.write( "= 2*sqrt(25)
\n" ); document.write( "=10 the width\r
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