document.write( "Question 1079429: A computer that, when purchased 5 years ago cost $5,000 now has a value of $1,100. Find the value of the computer after 8 years by using the exponential model V(t) = V_0e^kt, in which V(t) is the value of the computer at any time t, V_0 is the initial cost, and t is the time in years. Round your answer to the nearest hundredth. Any help is appreciated (: \n" ); document.write( "
Algebra.Com's Answer #837870 by mananth(16946)\"\" \"About 
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Formula
\n" ); document.write( "V(t) = V_0e^kt,\r
\n" ); document.write( "\n" ); document.write( "1100 = 5000 *e^5k \r
\n" ); document.write( "\n" ); document.write( "1100/5000 = e^5k\r
\n" ); document.write( "\n" ); document.write( "take the natural log of both sides \r
\n" ); document.write( "\n" ); document.write( "ln(1100/5000) = ln(e^(5k))\r
\n" ); document.write( "\n" ); document.write( "ln(1100/5000) =5k\r
\n" ); document.write( "\n" ); document.write( "k = ln(1100/5000) / 5 = -.3028255465 (decay constant)\r
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\n" ); document.write( "\n" ); document.write( " Vt= V0 * e^(kt)
\n" ); document.write( "t=8 , V0 =5000, k we have found out\r
\n" ); document.write( "\n" ); document.write( "Plug the value of in Vt = pV0* e^(kt) = 5000*e^(0-.3028255465*8)=443.45\r
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