document.write( "Question 1168293: A carpenter had two apprentices for a job. The carpenter worked 6 hours longer than the first apprentice. The second apprentice worked twice as long as the first. If the carpenter and his apprentices worked a total of 22 hours, how long did the carpenter work? \n" ); document.write( "

Algebra.Com's Answer #837837 by MathTherapy(10552) $\"\"$ $\"About$

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document.write( "A carpenter had two apprentices for a job. The carpenter worked 6 hours longer than the first apprentice. The second apprentice worked twice as long as the first. If the carpenter and his apprentices worked a total of 22 hours, how long did the carpenter work?\r\n" );
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document.write( "Let amount of hours carpenter worked be C \r\n" );
document.write( "Then 1st apprentice worked C - 6 hours, and 3rd apprentice worked: 2(C - 6) = 2C - 12 hours\r\n" );
document.write( "As all 3 worked for a total of 22 hours, we get: C + C - 6 + 2C - 12 = 22\r\n" );
document.write( "                                                             4C - 18 = 22\r\n" );
document.write( "                                                                  4C = 40\r\n" );
document.write( "                             Number of hours carpenter worked, or

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