document.write( "Question 1168293: A carpenter had two apprentices for a job. The carpenter worked 6 hours longer than the first apprentice. The second apprentice worked twice as long as the first. If the carpenter and his apprentices worked a total of 22 hours, how long did the carpenter work? \n" ); document.write( "
Algebra.Com's Answer #837819 by mananth(16946)\"\" \"About 
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Let Frst apprentice work for x hours
\n" ); document.write( "second works 2x hours
\n" ); document.write( "Carpenter works for x+6 hours\r
\n" ); document.write( "\n" ); document.write( "Total 22 hours\r
\n" ); document.write( "\n" ); document.write( "x+2x+x+6 =22\r
\n" ); document.write( "\n" ); document.write( "4x+6 = 22
\n" ); document.write( "4x =16\r
\n" ); document.write( "\n" ); document.write( "divide by 4
\n" ); document.write( "x=4\r
\n" ); document.write( "\n" ); document.write( "Carpenter works for x+6 hours = 4+6 =10 hours\r
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