document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=115117>Question 115117</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone please help? I am having problems with this question and I need to turn in my homework on Saturday. Please help!!!!!!!\r<BR>\n" );
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document.write( "Consider the function f(x)=x^2+6x-2.<BR>\n" );
document.write( "a) Find h, the x-coordinate of the vertex of this parabola.<BR>\n" );
document.write( "b)Substitute the two whole number values immediately to the left and the right of h into the function to find the corresponding y. Fill in the table below. make sure your x values are in increasing order in your table.<BR>\n" );
document.write( "    x       y<BR>\n" );
document.write( "   ___     ___<BR>\n" );
document.write( "   ___     ___<BR>\n" );
document.write( "h= ___     ___<BR>\n" );
document.write( "   ___     ___<BR>\n" );
document.write( "   ___     ___\r<BR>\n" );
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document.write( "c) Use MS Excel to graph the function by plotting the points found in the table in part b.\r<BR>\n" );
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document.write( "Please, if anyone can help I will greatly appreciate it, I am totally confused with this one. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83779 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83779\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since your deadline is Saturday, I can help a little, but you may need to post your problem <BR>\n" );
document.write( "again to get additional help from other tutors. <BR>\n" );
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document.write( "You can tell by the fact that the x^2 term is positive that the graph of this function is <BR>\n" );
document.write( "a parabola that, as you move from left to right, falls to a minimum and then rises again ... in<BR>\n" );
document.write( "other words it models the shape of a cup that is upright.<BR>\n" );
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document.write( "The vertex of this parabola is the lowest point of the curve. h is the value of x where this<BR>\n" );
document.write( "curve is at the lowest point.<BR>\n" );
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document.write( "The quadratic formula applies to equations of the form ax^2 + bx + c = 0. By comparing<BR>\n" );
document.write( "this form to your function of x^2 + 6x - 2 you will see that a = 1, b = +6, and c = -2.<BR>\n" );
document.write( "The value of x at the vertex is given by -b/(2a). Substituting the values of \"b\" and \"a\" <BR>\n" );
document.write( "that we found in by comparing with the quadratic form results in:<BR>\n" );
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document.write( "x = -(+6)/(2*1) = -6/2 = -3<BR>\n" );
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document.write( "This means that the value of h is -3.<BR>\n" );
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document.write( "Now that you know this you can start to find f(x) by evaluating x^2 + 6x -2 at various <BR>\n" );
document.write( "values of x on both sides of x = -3. <BR>\n" );
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document.write( "For example, you can evaluate x^2 + 6x - 2 for x = -5, x = -4, x = -3, x = -2, and x = -1.<BR>\n" );
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document.write( "When x = -5, then you will find that x^2 + 6x - 2 = y = -7<BR>\n" );
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document.write( "When x = -4, then you will find that x^2 + 6x - 2 = y = -10<BR>\n" );
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document.write( "When x = -3, then you will find that x^2 + 6x - 2 = y = -11<BR>\n" );
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document.write( "When x = -2, then you will find that x^2 + 6x - 2 = y = -10<BR>\n" );
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document.write( "When x = -1, then you will find that x^2 + 6x - 2 = y = -7<BR>\n" );
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document.write( "If you plot these points, you should get an idea of the shape of the graph of y = x^2 + 6x - 2<BR>\n" );
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document.write( "Here is the graph that you should get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28600%2C600%2C-15%2C+10%2C+-15%2C+20%2C+x%5E2+%2B+6x+-+2%29 ALIGN=MIDDLE  ALT=\"graph%28600%2C600%2C-15%2C+10%2C+-15%2C+20%2C+x%5E2+%2B+6x+-+2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Hope this information helps you to get started on this problem. <BR>\n" );
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