document.write( "Question 1202709: It is common in many industrial areas to use a filling machine to fill boxes full of products. This occurs in the food
\n" ); document.write( "industry as well as other areas in which the product is used in the home, for example, detergent. These machines
\n" ); document.write( "are not perfect, and indeed they may A, fill to specification, B, underfill, and C, overfill. Generally, the practice
\n" ); document.write( "of underfilling is that which one hopes to avoid. Let P(B) = 0.001 while P(A) = 0.990.
\n" ); document.write( "i. Give P(C).
\n" ); document.write( "ii. What is the probability that the machine does not underfill?
\n" ); document.write( "iii. What is the probability that the machine either overfills or underfills?
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Algebra.Com's Answer #837773 by ikleyn(52874)\"\" \"About 
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\n" ); document.write( "It is common in many industrial areas to use a filling machine to fill boxes full of products.
\n" ); document.write( "This occurs in the food industry as well as other areas in which the product is used in the home,
\n" ); document.write( "for example, detergent. These machines are not perfect, and indeed they may
\n" ); document.write( "    A,   fill to specification,
\n" ); document.write( "    B,   underfill, and
\n" ); document.write( "    C,    overfill.
\n" ); document.write( "Generally, the practice of underfilling is that which one hopes to avoid.
\n" ); document.write( "Let P(B) = 0.001 while P(A) = 0.990.
\n" ); document.write( "    (a)   Give P(C).
\n" ); document.write( "    (b)   What is the probability that the machine does not underfill?
\n" ); document.write( "    (c)   What is the probability that the machine either overfills or underfills?
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\n" ); document.write( "\n" ); document.write( "        Obviously, the introduced terms describe disjoint events, \r
\n" ); document.write( "\n" ); document.write( "        that have zero intersections in the probability theory meaning.\r
\n" ); document.write( "\n" ); document.write( "        So, the probabilities of combinations of events are the sums of elementary events.\r
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document.write( "(a)  P(A) + P(B) + P(C) = 1.  \r\n" );
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document.write( "     THEREFORE,  P(C) = 1 - P(A) - P(B) = 1 - 0.990 - 0.001 = 0.009.    ANSWER\r\n" );
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document.write( "(b)  P(does not underfill) = P(not B) = 1 - P(B) = 1 - 0.001 = 0.999.   ANSWER\r\n" );
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document.write( "(c)  P(either overfills or underfills) = P(C) + P(B).\r\n" );
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document.write( "     Again, notice that we just know P(C) = 0.009 from (a).\r\n" );
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document.write( "     THEREFORE,  P(either overfills or underfills) = P(C) + P(B) = 0.009 + 0.001 = 0.01.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "It is very easy problem, and its major goal is to check if the student is able to read the problem,
\n" ); document.write( "to understand the basic terms and their inter-relations, and to check
\n" ); document.write( "if he (or she) knows basic relations/formulas of the elementary probability theory.\r
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\n" ); document.write( "\n" ); document.write( "I specially re-formatted the text in your post for easy reading.\r
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\n" ); document.write( "\n" ); document.write( "This problem is good for those who make their first steps in learning the probability theory.\r
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\n" ); document.write( "\n" ); document.write( "For all other persons, the solution is more than evident.\r
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