document.write( "Question 1202709: It is common in many industrial areas to use a filling machine to fill boxes full of products. This occurs in the food
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document.write( "industry as well as other areas in which the product is used in the home, for example, detergent. These machines
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document.write( "are not perfect, and indeed they may A, fill to specification, B, underfill, and C, overfill. Generally, the practice
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document.write( "of underfilling is that which one hopes to avoid. Let P(B) = 0.001 while P(A) = 0.990.
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document.write( "i. Give P(C).
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document.write( "ii. What is the probability that the machine does not underfill?
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document.write( "iii. What is the probability that the machine either overfills or underfills? \n" );
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Algebra.Com's Answer #837773 by ikleyn(52874) You can put this solution on YOUR website! . \n" ); document.write( "It is common in many industrial areas to use a filling machine to fill boxes full of products. \n" ); document.write( "This occurs in the food industry as well as other areas in which the product is used in the home, \n" ); document.write( "for example, detergent. These machines are not perfect, and indeed they may \n" ); document.write( " A, fill to specification, \n" ); document.write( " B, underfill, and \n" ); document.write( " C, overfill. \n" ); document.write( "Generally, the practice of underfilling is that which one hopes to avoid. \n" ); document.write( "Let P(B) = 0.001 while P(A) = 0.990. \n" ); document.write( " (a) Give P(C). \n" ); document.write( " (b) What is the probability that the machine does not underfill? \n" ); document.write( " (c) What is the probability that the machine either overfills or underfills? \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Obviously, the introduced terms describe disjoint events, \r \n" ); document.write( "\n" ); document.write( " that have zero intersections in the probability theory meaning.\r \n" ); document.write( "\n" ); document.write( " So, the probabilities of combinations of events are the sums of elementary events.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "(a) P(A) + P(B) + P(C) = 1. \r\n" ); document.write( "\r\n" ); document.write( " THEREFORE, P(C) = 1 - P(A) - P(B) = 1 - 0.990 - 0.001 = 0.009. ANSWER\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "(b) P(does not underfill) = P(not B) = 1 - P(B) = 1 - 0.001 = 0.999. ANSWER\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "(c) P(either overfills or underfills) = P(C) + P(B).\r\n" ); document.write( "\r\n" ); document.write( " Again, notice that we just know P(C) = 0.009 from (a).\r\n" ); document.write( "\r\n" ); document.write( " THEREFORE, P(either overfills or underfills) = P(C) + P(B) = 0.009 + 0.001 = 0.01. ANSWER\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It is very easy problem, and its major goal is to check if the student is able to read the problem, \n" ); document.write( "to understand the basic terms and their inter-relations, and to check \n" ); document.write( "if he (or she) knows basic relations/formulas of the elementary probability theory.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I specially re-formatted the text in your post for easy reading.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This problem is good for those who make their first steps in learning the probability theory.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For all other persons, the solution is more than evident.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |