document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1202696>Question 1202696</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If tan x > 0, then tan (x/2) > 0. True or False? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #837769 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=837769\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "If x is between 0 and pi/2, then x/2 is between 0 and pi/4.  In that case, since tan(x) > 0 everywhere between 0 and pi/2, the statement is true.<br><BR>\n" );
document.write( "But if x is between pi and 3pi/2, then tan(x) is again positive.  But in this case, x/2 is between pi/2 and 3pi/4, so tan(x/2) < 0.  So in this case tan(x) > 0 but tan(x/2) < 0, so the statement is false.<br><BR>\n" );
document.write( "ANSWER: False<br><BR>\n" );
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