document.write( "Question 1202699: Solve equation, sin(2x) - sinx - 2cosx + 1 = 0, on the interval 0 < or equal x < 2pi. \n" ); document.write( "
Algebra.Com's Answer #837766 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! This is 2 sin x cos x-sinx -2cos x+1=0=sin x(2 cos x-1)-(2 cos x-1)=0 \n" ); document.write( "this is (sin x-1)(2cos x-1)=0 \n" ); document.write( "sin x=1 and cos x=1/2 \n" ); document.write( "This is at pi/3, pi/2, and 5pi/3 or 1.05, 1.57, 5.23\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |