document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1167309>Question 1167309</A>: <I><SPAN STYLE=\"word-break: break-all;\"> tim did 10 lunges on day 1 and continued this doing 4 more lunges on each day.on day 7th he took a break and did nt do any day day.what is the equation for this? express it in the form y=ax(x+b)+c, where a,b and c are constants.x= no of days and y=no of lunges tim did </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #837725 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=837725\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From day 1 to day 6, Tim did 10 lunges on the first day and added 4 more lunges each day. So, on day x \r<BR>\n" );
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document.write( "y = 4(x-1) + 10\r<BR>\n" );
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document.write( "Simplifying this equation, we get:\r<BR>\n" );
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document.write( "y = 4x + 6\r<BR>\n" );
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document.write( "day 7, y would be 0.\r<BR>\n" );
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document.write( " the equation for the number of lunges Tim did for 7 days will be\r<BR>\n" );
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document.write( "y = 4x + 6(x-1)(x<7) + 0           (Day 7 0)\r<BR>\n" );
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document.write( "Simplify\r<BR>\n" );
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document.write( "y = 4x - 18 (x<7)<BR>\n" );
document.write( "y = 4x(x-7) - 18  </SPAN>\n" );
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