document.write( "Question 114527: Find the equation of the parabola described: Focus at (0,2); vertex at (0,0). Graph the parabola and the directrix. Please explain. Thanks \n" ); document.write( "
Algebra.Com's Answer #83771 by solver91311(24713)\"\" \"About 
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The first thing we know about this parabola is that the axis of symmetry is the line x = 0. We know this because the both the focus and the vertex have to lie on the same line and the only line that passes through both (0,2) and (0,0) is x = 0, or the y-axis.\r
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\n" ); document.write( "\n" ); document.write( "The next thing is to determine the distance between the focus and the vertex. We can really just tell by inspection that the distance is 2 because both points are on a vertical line with the y coordinates differing by 2. But, just to show the general case, lets use the distance formula:\r
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\n" ); document.write( "\n" ); document.write( "Now the equation for a parabola is \"4p%28y-k%29=%28x-h%29%5E2\" where p is the distance from the focus to the vertex, and the vertex is at point(h,k). So,\r
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\n" ); document.write( "\n" ); document.write( "\"4%282%29%28y-0%29=%28x-0%29%5E2\"
\n" ); document.write( "\"8y=x%5E2\"
\n" ); document.write( "\"y=%28x%5E2%29%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "The directrix is a line perpendicular to the axis of symmetry -p units distant from the vertex. Since our parabola has a vertical line as an axis of symmetry, the directrix must be a horizontal line. The only horizontal line that is -2 units from the vertex (0,0) is y = -2.\r
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\n" ); document.write( "\n" ); document.write( "The green line is the directrix\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28600%2C600%2C-10%2C10%2C-10%2C10%2Cx%5E2%2F8%2C-2%29\"
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