document.write( "Question 1070331: in a cricket match,bye runs were double of the no-balls.the remaining scpre was greater by six then twelve times the number of bye runs.if the total score 276,how were the runs obtained??? \n" ); document.write( "
Algebra.Com's Answer #837696 by mananth(16946)\"\" \"About 
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Let the number of no-balls in the match be 'x'. Then, the number of bye runs is '2x'
\n" ); document.write( " the remaining score is greater by six than twelve times the number of bye runs.\r
\n" ); document.write( "\n" ); document.write( "Remaining score = 12(2x) + 6 = 24x + 6\r
\n" ); document.write( "\n" ); document.write( "Total score = Remaining score + Bye runs + No-balls\r
\n" ); document.write( "\n" ); document.write( "Substituting the values, we get:\r
\n" ); document.write( "\n" ); document.write( "276 = 24x + 6 + 2x + x\r
\n" ); document.write( "\n" ); document.write( "Simplify\r
\n" ); document.write( "\n" ); document.write( "276 = 27x + 6\r
\n" ); document.write( "\n" ); document.write( "270 = 27x\r
\n" ); document.write( "\n" ); document.write( "x = 10\r
\n" ); document.write( "\n" ); document.write( " no-balls in the match is 10. Therefore, the number of bye runs is 20.\r
\n" ); document.write( "\n" ); document.write( "Total score = Remaining score + Bye runs + No-balls\r
\n" ); document.write( "\n" ); document.write( "Total score = (12 * 20) + 6 + 20 + 10\r
\n" ); document.write( "\n" ); document.write( "Total score = 276
\n" ); document.write( " hitting the ball: 246
\n" ); document.write( " bye runs: 20
\n" ); document.write( "no-balls: 10
\n" ); document.write( " \n" ); document.write( "
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