document.write( "Question 1202680: Two cars left a station in Bawku and were travelling to Tamale a distance of 135km away. The second car left 30 minutes after the first car had left. If the speed of the second car is 3/2 times as fast as the first car, and the second car got to Tamale 45 minutes before the first car arrived
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Algebra.Com's Answer #837672 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "Two cars left a station in Bawku and were travelling to Tamale a distance of 135km away.
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\n" ); document.write( "and the second car got to Tamale 45 minutes before the first car arrived,
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document.write( "Let v be the speed of the first car, in kilometers per hour.\r\n" );
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document.write( "Then the speed of the second car is  \"%283%2F2%29%2Av\",  according to the problem.\r\n" );
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document.write( "The travel time of the first car is  \"135%2Fv\"  hours.\r\n" );
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document.write( "The travel time of the second car is  \"135%2F%28%283%2F2%29%2Av%29\" hours, which is the same as  \"90%2Fv\".\r\n" );
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document.write( "The difference of the travel times is 30 + 45 minutes = 75 minutes = \"75%2F60\" hours = \"5%2F4\" hours.\r\n" );
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document.write( "So we write this \"time equation\"\r\n" );
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document.write( "    \"135%2Fv\" - \"90%2Fv\" = \"5%2F4\".\r\n" );
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document.write( "Simplifying left side, we get\r\n" );
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document.write( "    \"45%2Fv\" = \"5%2F4\".\r\n" );
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document.write( "Thus we find\r\n" );
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document.write( "    v = \"%2845%2A4%29%2F5\" = 9*4 = 36.\r\n" );
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document.write( "ANSWER.  The speed of the first car is  36 km/h.\r\n" );
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document.write( "         The speed of the second car is  \"%283%2F2%29%2A36\" = 3*18 = 54 km/h.\r\n" );
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