document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1202668>Question 1202668</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Which term of the series 2187,729,243....is 1/9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #837646 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=837646\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Which term of the series 2187,729,243....is 1/9\r<BR>\n" );
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document.write( "The formula\r<BR>\n" );
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document.write( "a1 =2187\r<BR>\n" );
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document.write( "r= 729/2187 = 1/3\r<BR>\n" );
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document.write( "1/9 = 2187*(1/3)^(n-1)\r<BR>\n" );
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document.write( "(1/3)^(n-1) = 1/9*2187=1/19683 = (1/3)^9<BR>\n" );
document.write( "using exponent rules\r<BR>\n" );
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document.write( " n=10\r<BR>\n" );
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document.write( " </SPAN>\n" );
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