document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1202656>Question 1202656</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much 9% saline solution should Kent mix with 70 cubic centimeters (cc) of a 17% saline solution to produce a 13% saline solution?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #837632 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=837632\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The formal algebraic solutions in the responses from the other tutors are fine.<br><BR>\n" );
document.write( "But as one of the tutors notes at the end of his response, the formal algebra is not needed.  Common sense tells us that, since 13% is exactly halfway between 9% and 17%, the amount of 9% saline should be equal to the amount of 17% saline.<br><BR>\n" );
document.write( "That tutor implies that solving the problem by that method only works when the percentage of the mixture is halfway between the percentages of the two ingredients.<br><BR>\n" );
document.write( "But that is not the case.  That informal method can be used to solve any 2-part mixture problem quickly and easily.  In this problem, the percentage of the mixture is 1/2 of the way from the 9% to the 17%, so half of the mixture is the 17% saline.  If in a similar problem the percentage of the mixture is 2/5 of the way from the lower percentage to the higher percentage, then 2/5 of the mixture would have to be the higher percentage ingredient.<br><BR>\n" );
document.write( "You should be able to search this website for many examples of problems like this for which I have provided responses showing solutions by this quick informal method.<br><BR>\n" );
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