document.write( "Question 1202648: Bob and his brother Jim live 95 miles apart and like to meet and play golf together, the course is 15 miles further for Bob as it is from Jim but Bob averages 10 mph faster than Jim so if they want to meet at the course at 9:00 and Jim leaves at 8:00 what time would Bob need to leave? \n" ); document.write( "
Algebra.Com's Answer #837616 by mananth(16946)\"\" \"About 
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Bob and his brother Jim live 95 miles apart and like to meet and play golf together, the course is 15 miles further for Bob as it is from Jim but Bob averages 10 mph faster than Jim so if they want to meet at the course at 9:00 and Jim leaves at 8:00 what time would Bob need to leave?\r
\n" ); document.write( "\n" ); document.write( "Jim's distance = 15 miles
\n" ); document.write( "Time taken by Jim = 1 hour (8.00 to 9.00)\r
\n" ); document.write( "\n" ); document.write( "Jim's speed = 15 mph\r
\n" ); document.write( "\n" ); document.write( "Bob's speed = 15+10 =25 mph\r
\n" ); document.write( "\n" ); document.write( "Bob has to travel 95+15 = 110 miles
\n" ); document.write( "t =d/s\r
\n" ); document.write( "\n" ); document.write( "110/25 = 4.4 hour\r
\n" ); document.write( "\n" ); document.write( "Bob has to leave 3.4 hours earlier than Jim\r
\n" ); document.write( "\n" ); document.write( "0.4 hour = 24 minutes\r
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