document.write( "Question 1202567: The sum of 2000 numbers is 2007. Find maximum product of these numbers. (There are more than one set of such numbers) \n" ); document.write( "
Algebra.Com's Answer #837517 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "By a general principle, given a set of numbers with a particular sum, the maximum product of the numbers is when the numbers are all equal.

\n" ); document.write( "2000 numbers, all equal, with a sum of 2007, means each number is 2007/2000.

\n" ); document.write( "The maximum product is

\n" ); document.write( "ANSWER: \"%282007%2F2000%29%5E2000\".

\n" ); document.write( "Note the problem is not defined precisely enough. If some of the numbers are allowed to be negative, then there is no maximum product. Given a positive number x, the set consisting of -x, -1, 1997 1's, and x+11 has a sum of 2007, and the product of the numbers is x(x+11), which clearly has no maximum.

\n" ); document.write( "
\n" ); document.write( "
\n" );