document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1202588>Question 1202588</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a + 2b = 3c and 2a + 4b + c = 56 what is the value of c?\r<BR>\n" );
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document.write( "(A) -12<BR>\n" );
document.write( "(B) -4<BR>\n" );
document.write( "(C) 8<BR>\n" );
document.write( "(D) 12<BR>\n" );
document.write( "(E) 24 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #837512 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=837512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "(1) a+2b = 3c<BR>\n" );
document.write( "(2) 2a+4b+c = 56<br><BR>\n" );
document.write( "In the second equation, \"2a+4b\" is \"a+2b\" times 2; and the first equation gives us the value of \"a+2b\" in terms of c:<br><BR>\n" );
document.write( "2a+4b+c = 56<BR>\n" );
document.write( "2(a+2b)+c = 56<BR>\n" );
document.write( "2(3c)+c = 56<BR>\n" );
document.write( "6c+c = 56<BR>\n" );
document.write( "7c = 56<BR>\n" );
document.write( "c = 8<br><BR>\n" );
document.write( "ANSWER: (C) 8<br><BR>\n" );
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