document.write( "Question 1202558: Ron borrowed $1800 to finance a computer at 15.6%/a compounded monthly for 1 1/2 years.
\n" ); document.write( "a) How much will his monthly payments be?
\n" ); document.write( "b) How much more would Ron have to pay per month to pay the loan off 6 months early?
\n" ); document.write( "c) How much interest would Ron save if he paid the loan off early?\r
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Algebra.Com's Answer #837475 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Answers
\n" ); document.write( "(a) $112.80 per month
\n" ); document.write( "(b) $50.18 more
\n" ); document.write( "(c) He saves $74.64\r
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\n" ); document.write( "\n" ); document.write( "Work Shown for part (a)\r
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\n" ); document.write( "\n" ); document.write( "The formula to use is
\n" ); document.write( "P = (L*i)/( 1-(1+i)^(-n) )
\n" ); document.write( "where,
\n" ); document.write( "P = monthly payment
\n" ); document.write( "L = loan amount
\n" ); document.write( "i = monthly interest rate in decimal form
\n" ); document.write( "n = number of months\r
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\n" ); document.write( "\n" ); document.write( "In this case
\n" ); document.write( "L = 1800
\n" ); document.write( "i = 0.156/12 = 0.013 exactly
\n" ); document.write( "n = 1.5*12 = 18 months\r
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\n" ); document.write( "\n" ); document.write( "We can now compute the monthly payment.
\n" ); document.write( "P = (L*i)/( 1-(1+i)^(-n) )
\n" ); document.write( "P = (1800*0.013)/( 1-(1+0.013)^(-18) )
\n" ); document.write( "P = 112.801552357259
\n" ); document.write( "P = 112.80\r
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\n" ); document.write( "\n" ); document.write( "Ron's monthly payment is $112.80
\n" ); document.write( "It can be verified through use of a calculator such as this
\n" ); document.write( "https://www.calculator.net/loan-calculator.html\r
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\n" ); document.write( "\n" ); document.write( "Work Shown for part (b)\r
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\n" ); document.write( "\n" ); document.write( "If he is required to pay back the loan 6 months early, then the 18 month time frame shrinks to 18-6 = 12 months.\r
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\n" ); document.write( "\n" ); document.write( "We'll use n = 12 this time but keep the other values the same.\r
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\n" ); document.write( "\n" ); document.write( "P = (L*i)/( 1-(1+i)^(-n) )
\n" ); document.write( "P = (1800*0.013)/( 1-(1+0.013)^(-12) )
\n" ); document.write( "P = 162.975019846114
\n" ); document.write( "P = 162.98\r
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\n" ); document.write( "\n" ); document.write( "Ron's monthly payment is now $162.98\r
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\n" ); document.write( "\n" ); document.write( "Subtract the previous monthly payment to find the increase.
\n" ); document.write( "162.98 - 112.80 = 50.18\r
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\n" ); document.write( "\n" ); document.write( "He must pay $50.18 more per month if he wants to pay the loan back 6 months early.\r
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\n" ); document.write( "\n" ); document.write( "Work Shown for part (c)\r
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\n" ); document.write( "\n" ); document.write( "In part (a) we found Ron's monthly payment was $112.80
\n" ); document.write( "Over the course of 18 months, he pays back a total of 18*112.80 = 2030.40 dollars.
\n" ); document.write( "The interest is 2030.40 - 1800 = 230.40 dollars.\r
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\n" ); document.write( "\n" ); document.write( "In part (b) we found Ron's monthly payment was $162.98
\n" ); document.write( "Over the course of 12 months, he pays back a total of 12*162.98 = 1955.76 dollars.
\n" ); document.write( "The interest is 1955.76 - 1800 = 155.76 dollars.\r
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\n" ); document.write( "\n" ); document.write( "As you can see, Ron paying more per month has the advantage of paying less overall interest.\r
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\n" ); document.write( "\n" ); document.write( "Subtract the interest amounts to determine how much he saves.
\n" ); document.write( "230.40 - 155.76 = 74.64\r
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\n" ); document.write( "\n" ); document.write( "He would save $74.64 if he pays back the loan 6 months early.
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