document.write( "Question 1202547: Horses sold for $400 each and ponies for only $100. Weir spent $4500 and bought 5 more horses than ponies. How many horses did she buy? \n" ); document.write( "
Algebra.Com's Answer #837469 by greenestamps(13216) You can put this solution on YOUR website! \n" ); document.write( "While a formal algebraic solution was probably wanted, note that you can get good mental exercise, and good problem-solving practice, by solving the problem informally using logical reasoning and simple mental arithmetic. \n" ); document.write( "In this problem, she bought 5 more horses than ponies. Those 5 \"extra\" horses cost 5($400) = $2000. \n" ); document.write( "Beyond that, there were equal numbers of horses and ponies with a total cost of $4500-$2000 = $2500. \n" ); document.write( "The cost of one horse and one pony is $400+$100 = $500; to make the additional $2500 cost, the remaining number of horses and ponies must have been $2500/$500 = 5. \n" ); document.write( "So the number of ponies she bought was 5, and the number of horses she bought was 5+5 = 10. \n" ); document.write( "ANSWER: 10 horses (and 5 ponies) \n" ); document.write( "CHECK: 10($400)+5($100) = $4500 \n" ); document.write( " \n" ); document.write( " |