document.write( "Question 1202534: Marcel has a jar filled with one and five dollar bills. The jar contains 34 bills and totals $110. How many bills of each type does he have?\r
\n" ); document.write( "\n" ); document.write( "Number of one dollar bills\r
\n" ); document.write( "\n" ); document.write( "Number of five dollar bills
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Algebra.Com's Answer #837427 by Theo(13342)\"\" \"About 
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x = number of 1 dollar bills.
\n" ); document.write( "y = number of 5 dollar bills.
\n" ); document.write( "jar contains 34 bills
\n" ); document.write( "x + y = 34
\n" ); document.write( "total money in the jar is 110 dollars.
\n" ); document.write( "x + 5y = 110
\n" ); document.write( "solve for y in the first equqtion to get:
\n" ); document.write( "y = 34 - x
\n" ); document.write( "replace y in the second equation with tha to get:
\n" ); document.write( "x + 5 * (34 - x) = 110
\n" ); document.write( "simplify to get:
\n" ); document.write( "x + 170 - 5x = 110
\n" ); document.write( "combine like terms to get:
\n" ); document.write( "-4x + 170 = 110
\n" ); document.write( "add 4x to both sides of the equation and subtract 110 from both sides of the equation to get:
\n" ); document.write( "60 = 4x
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = 15
\n" ); document.write( "since x + y = 34, then y must be equal to 19.
\n" ); document.write( "x + y becomes 15 + 19 which is equal to 34.
\n" ); document.write( "x + 5y becomes 15 + 95 which is equal to 110.
\n" ); document.write( "values look good.
\n" ); document.write( "solution is he has 15 one dollar bills and 19 five dollars bills.
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