document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1202494>Question 1202494</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Good ones were $7 each and sorry ones were only $3 each. If Fiona spent $414 and bought 2 more good ones than sorry ones, how many of each did she buy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #837351 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=837351\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x is the number of sorry ones.<BR>\n" );
document.write( "x + 2 is the number of good ones.<BR>\n" );
document.write( "7 * (x + 2) + 3 * x = 414<BR>\n" );
document.write( "simplify t get 7x + 14 + 3x = 414<BR>\n" );
document.write( "combine like terms to get 10x + 14 = 414<BR>\n" );
document.write( "subtract 14 from both sides of the equation to get 10x = 400<BR>\n" );
document.write( "solve for x to get x = 40<BR>\n" );
document.write( "comfirn by replacing x in the original euqtion to get 7 * 42 + 3 * 40 = 414<BR>\n" );
document.write( "simplify to get 294 + 120 = 414<BR>\n" );
document.write( "combine like terms to get 414 = 414, confirming the value of x is correct.<BR>\n" );
document.write( "your solution is she bought 42 good ones and 40 sorry ones.\r<BR>\n" );
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