document.write( "Question 1202488: Log7(3x)+log7(2x-1)=log7(16x-10) \n" ); document.write( "
Algebra.Com's Answer #837346 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Answers: \"x+=+5%2F2+\" and \"+x+=+2%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Work Shown:\r
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\n" ); document.write( "\n" ); document.write( "All logs for this problem are base 7
\n" ); document.write( "log(3x) + log(2x-1) = log(16x-10)
\n" ); document.write( "log(3x*(2x-1)) = log(16x-10) ..... log rule log(A)+log(B) = log(A*B)
\n" ); document.write( "3x*(2x-1) = 16x-10
\n" ); document.write( "6x^2-3x = 16x-10
\n" ); document.write( "6x^2-3x-16x+10 = 0
\n" ); document.write( "6x^2-19x+10 = 0\r
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\n" ); document.write( "\n" ); document.write( "Now use the quadratic formula
\n" ); document.write( "a = 6
\n" ); document.write( "b = -19
\n" ); document.write( "c = 10
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28b%5E2+-+4ac%29%29%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-19%29+%2B-+sqrt%28%28-19%29%5E2+-+4%286%29%2810%29%29%29%2F%282%286%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2819+%2B-+sqrt%28361-240%29%29%2F%282%286%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2819+%2B-+sqrt%28121%29%29%2F%2812%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2819+%2B-+11%29%2F%2812%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2819+%2B+11%29%2F%2812%29+\" or \"+x+=+%2819+-+11%29%2F%2812%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2830%29%2F%2812%29+\" or \"+x+=+%288%29%2F%2812%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+5%2F2+\" or \"+x+=+2%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "From here we need to check each possible solution.
\n" ); document.write( "I'll let the student do this part. Plug each x value one at a time into the original equation. Simplify both sides.
\n" ); document.write( "You should find that both x values work.
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