document.write( "Question 1202488: Log7(3x)+log7(2x-1)=log7(16x-10) \n" ); document.write( "
Algebra.Com's Answer #837346 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answers: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Work Shown:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "All logs for this problem are base 7 \n" ); document.write( "log(3x) + log(2x-1) = log(16x-10) \n" ); document.write( "log(3x*(2x-1)) = log(16x-10) ..... log rule log(A)+log(B) = log(A*B) \n" ); document.write( "3x*(2x-1) = 16x-10 \n" ); document.write( "6x^2-3x = 16x-10 \n" ); document.write( "6x^2-3x-16x+10 = 0 \n" ); document.write( "6x^2-19x+10 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now use the quadratic formula \n" ); document.write( "a = 6 \n" ); document.write( "b = -19 \n" ); document.write( "c = 10 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From here we need to check each possible solution. \n" ); document.write( "I'll let the student do this part. Plug each x value one at a time into the original equation. Simplify both sides. \n" ); document.write( "You should find that both x values work. \n" ); document.write( " \n" ); document.write( " |