document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=114912>Question 114912</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hey,<BR>\n" );
document.write( "i couldn't find the answer of this equation, could u please solve it for me.<BR>\n" );
document.write( "okay. A radius of a circle has end points at O(-1,3) and R(2,2). Find two possible end points for the diameter that contains the radius.\r<BR>\n" );
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document.write( "And thank you,<BR>\n" );
document.write( "i will be waiting for the answer.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83734 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83734\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a diameter is twice the radius, actually two radii end-to-end\r<BR>\n" );
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document.write( "the two end points given in the queation could be end points of diameters, depending on which end another radius is added\r<BR>\n" );
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document.write( "going from O to R, adds 3 to the x value and -1 to the y; so the other end of a diameter starting at O would be (5,1)\r<BR>\n" );
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document.write( "similarly, R to O is -3 in x an 1 in y; the other end of a diameter starting at R would be (-4,4) </SPAN>\n" );
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