document.write( "Question 1202469: The 3rd term of a geometric sequence is 36, and the 6th term is 9/2. What is the recursive formula for the sequence? \n" ); document.write( "
Algebra.Com's Answer #837334 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The 3rd term, 36, is the first term, multiplied by the common ratio 2 times: \"ar%5E2=36\".

\n" ); document.write( "The 6th term, 9/2, is the first term, multiplied by the common ratio 5 times: \"ar%5E5=9%2F2\".

\n" ); document.write( "Divide the formulas for the 6th and 3rd terms to calculate the common ratio:

\n" ); document.write( "\"r%5E3=%289%2F2%29%2F36=1%2F8\"
\n" ); document.write( "\"r=1%2F2\"

\n" ); document.write( "A RECURSIVE formula tells how to get each term from the preceding term; for a geometric sequence the rule is \"multiply by the common ratio\". Since in this problem the common ratio is 1/2, the recursive formula is

\n" ); document.write( "\"a%28n%29=%281%2F2%29%2Aa%28n-1%29\"

\n" ); document.write( "To complete the definition of the recursive formula for the sequence, we need to specify the first term. Since the 3rd term is 36 and the common ratio is 1/2,

\n" ); document.write( "\"36=a%28%281%2F2%29%5E2%29\"
\n" ); document.write( "\"36=a%2F4\"
\n" ); document.write( "\"a=144\"

\n" ); document.write( "ANSWER: a(1)=144; for n>1, a(n)=(1/2)*a(n-1)

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