document.write( "Question 1202469: The 3rd term of a geometric sequence is 36, and the 6th term is 9/2. What is the recursive formula for the sequence? \n" ); document.write( "
Algebra.Com's Answer #837326 by mananth(16946)![]() ![]() You can put this solution on YOUR website! The 3rd term of a geometric sequence is 36, and the 6th term is 9/2. What is the recursive formula for the sequence\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "tn = ar^(n-1)\r \n" ); document.write( "\n" ); document.write( "t3= a*r^(3-1)\r \n" ); document.write( "\n" ); document.write( "t3= ar^2=36\r \n" ); document.write( "\n" ); document.write( "t6 = a*r(6-1) = ar^5= 9/2\r \n" ); document.write( "\n" ); document.write( "t3/t6 = ar^2/ar^5 = 36/(9/2)\r \n" ); document.write( "\n" ); document.write( "1/r^3= 36/9 *2\r \n" ); document.write( "\n" ); document.write( "1/r^3= 8 \n" ); document.write( "r^3= 1/8\r \n" ); document.write( "\n" ); document.write( "r=1/2\r \n" ); document.write( "\n" ); document.write( "ar^2=36\r \n" ); document.write( "\n" ); document.write( "plug r\r \n" ); document.write( "\n" ); document.write( "a*(1/2)^2 =36 \n" ); document.write( "a/4 =36 \n" ); document.write( "a= 144\r \n" ); document.write( "\n" ); document.write( "tn = 144*(1/2)^n-1\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |