document.write( "Question 1202469: The 3rd term of a geometric sequence is 36, and the 6th term is 9/2. What is the recursive formula for the sequence? \n" ); document.write( "
Algebra.Com's Answer #837326 by mananth(16946)\"\" \"About 
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The 3rd term of a geometric sequence is 36, and the 6th term is 9/2. What is the recursive formula for the sequence\r
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\n" ); document.write( "\n" ); document.write( "tn = ar^(n-1)\r
\n" ); document.write( "\n" ); document.write( "t3= a*r^(3-1)\r
\n" ); document.write( "\n" ); document.write( "t3= ar^2=36\r
\n" ); document.write( "\n" ); document.write( "t6 = a*r(6-1) = ar^5= 9/2\r
\n" ); document.write( "\n" ); document.write( "t3/t6 = ar^2/ar^5 = 36/(9/2)\r
\n" ); document.write( "\n" ); document.write( "1/r^3= 36/9 *2\r
\n" ); document.write( "\n" ); document.write( "1/r^3= 8
\n" ); document.write( "r^3= 1/8\r
\n" ); document.write( "\n" ); document.write( "r=1/2\r
\n" ); document.write( "\n" ); document.write( "ar^2=36\r
\n" ); document.write( "\n" ); document.write( "plug r\r
\n" ); document.write( "\n" ); document.write( "a*(1/2)^2 =36
\n" ); document.write( "a/4 =36
\n" ); document.write( "a= 144\r
\n" ); document.write( "\n" ); document.write( "tn = 144*(1/2)^n-1\r
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