document.write( "Question 1202456: a car travels from point C northward for 1 hr then eastward for half an hour, then shifted N 30 E. if the constant speed of the car is 40kph, how far directly from point c will it be after 2 hrs. \n" ); document.write( "
Algebra.Com's Answer #837312 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Answer: 64.6965 km (approximate)\r
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\n" ); document.write( "\n" ); document.write( "Explanation:\r
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\n" ); document.write( "\n" ); document.write( "Draw an xy axis.
\n" ); document.write( "Place point C at the origin.\r
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\n" ); document.write( "\n" ); document.write( "The car drives north at 40 kph for 1 hour.
\n" ); document.write( "Distance = rate*time
\n" ); document.write( "Distance = (40 kph)*(1 hr)
\n" ); document.write( "Distance = 40 km
\n" ); document.write( "The car drives 40 km north for the first leg of the trip.
\n" ); document.write( "Move from point C(0,0) to point A(0,40)\r
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\n" ); document.write( "\n" ); document.write( "For the next leg of the trip, we have
\n" ); document.write( "Distance = rate*time
\n" ); document.write( "Distance = (40 kph)*(1/2 hr)
\n" ); document.write( "Distance = 20 km
\n" ); document.write( "This will move us from A(0,40) to B(20,40) when going 20 km east.\r
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\n" ); document.write( "\n" ); document.write( "The notation N 30 E means \"face north, then turn 30 degrees eastward\".
\n" ); document.write( "This is equivalent to the notation E 60 N where we face east and then turn 60 degrees toward the north.
\n" ); document.write( "30+60 = 90
\n" ); document.write( "See this page for more info about compass bearings.
\n" ); document.write( "http://academic.brooklyn.cuny.edu/geology/leveson/core/linksa/comp.html\r
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\n" ); document.write( "\n" ); document.write( "The notation E 60 N is more useful because 60 degrees is the reference angle.
\n" ); document.write( "Use polar coordinates as an offset to move from B(20,40) to D(30,57.320508)\r
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\n" ); document.write( "\n" ); document.write( "The scratch work to determine the x,y coordinates of D are shown in this paragraph
\n" ); document.write( "r = distance traveled for the remaining 1/2 hr = 20 km
\n" ); document.write( "theta = 60 degree reference angle
\n" ); document.write( "(xB,yB) = x and y coordinates of point B
\n" ); document.write( "x = xB + r*cos(theta)
\n" ); document.write( "x = 20 + 20*cos(60)
\n" ); document.write( "x = 30
\n" ); document.write( "y = yB + r*sin(theta)
\n" ); document.write( "y = 40 + 20*sin(60)
\n" ); document.write( "y = 57.320508 which is approximate
\n" ); document.write( "Make sure your calculator is in degree mode.\r
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\n" ); document.write( "\n" ); document.write( "To recap the journey:
  • Start at C(0,0)
  • Move 40 km north to arrive at A(0,40)
  • Move 20 km east to get to B(20,40)
  • Move 20 km along the compass bearing N 30 E (aka E 60 N) to arrive at the approximate location D(30,57.320508)
The pathway is C to A to B to D in that exact order.\r
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\n" ); document.write( "\n" ); document.write( "The question is: how far is it from the start point C(0,0) to the end point D(30,57.320508)?\r
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\n" ); document.write( "\n" ); document.write( "We could draw a right triangle and use the pythagorean theorem.
\n" ); document.write( "Or we could use the distance formula.\r
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\n" ); document.write( "\n" ); document.write( "I'll use the distance formula.
\n" ); document.write( "(x1,y1) = (0,0) and (x2,y2) = (30,57.320508)
\n" ); document.write( "\"d+=+sqrt%28+%28x1-x2%29%5E2+%2B+%28y1-y2%29%5E2+%29\"
\n" ); document.write( "\"d+=+sqrt%28+%280-30%29%5E2+%2B+%280-57.320508%29%5E2+%29\"
\n" ); document.write( "\"d+=+sqrt%28+%28-30%29%5E2+%2B+%28-57.320508%29%5E2+%29\"
\n" ); document.write( "\"d+=+sqrt%28+900+%2B+3285.64063737806+%29\"
\n" ); document.write( "\"d+=+64.6965272435706\"
\n" ); document.write( "\"d+=+64.6965\"
\n" ); document.write( "This is the approximate distance from C(0,0) to D(30,57.320508)
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