document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1202459>Question 1202459</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A certain car uses 15 gal of gasoline in 3 h. If the rate of gasoline consumption is constant, how much gasoline will the car use on a 35-hour trip? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #837307 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13206)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=837307\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Using a proportion, as the other tutor did, is one good formal way for solving the problem.<br><BR>\n" );
document.write( "A slightly less formal way, given that the rate of fuel consumption is constant, is to multiply the given number of gallons of gas by the ratio of the two times:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15%2A%2835%2F3%29+=+%2815%2A35%29%2F3+=+5%2A35+=+175 ALIGN=MIDDLE  ALT=\"15%2A%2835%2F3%29+=+%2815%2A35%29%2F3+=+5%2A35+=+175\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "ANSWER: 175 gallons<br><BR>\n" );
document.write( "And a third easy solution method is to use the given data to determine the rate of fuel consumption in gallons per hour and multiply that number by 35 hours:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15%2F3=5 ALIGN=MIDDLE  ALT=\"15%2F3=5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2A35=175 ALIGN=MIDDLE  ALT=\"5%2A35=175\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "The actual calculation in all three solution methods is the same; so the choice of which method is up to the student -- find the method that \"works\" for you an use it.<br><BR>\n" );
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