document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1202430>Question 1202430</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sketch q figure and solve each right triangle ABC with right angle at C.<BR>\n" );
document.write( "1. A = 76° and a = 13<BR>\n" );
document.write( "2. A = 22° and b = 22<BR>\n" );
document.write( "3. B = 30° and b = 11<BR>\n" );
document.write( "4. B = 18° and a = 18<BR>\n" );
document.write( "5. A = 77° and b = 42<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #837263 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39627)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=837263\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Straightforward exercise;<BR>\n" );
document.write( "what trouble are you having?\r<BR>\n" );
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document.write( "Only commenting or helping #3:<BR>\n" );
document.write( "Draw it!  You have a 30-60-90 right triangle.  You know this comes from half of a equilateral triangle.  Therefore you will figure that c  is two times b; so c=22.  IF necessary (may not be depending what you know), Pythagorean Theorem will give you length a.  You already know angle at A is 60 degrees. </SPAN>\n" );
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