document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1202419>Question 1202419</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There was $2900 in the pot. If there were 293 more $1 bills than $10 bills, how many bills of each kind were there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #837261 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13209)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=837261\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is an informal solution using logical reasoning and simple arithmetic.  Compare it to the solution from tutor @math_tutor2020 to see that the formal algebra does exactly what the informal solution does.<br><BR>\n" );
document.write( "Subtract the \"extra\" 293 $1 bills from the total, leaving equal numbers of $1 and $10 bills with a total value of $2900-$293 = $2607.<br><BR>\n" );
document.write( "The total value of one $1 bill and one $10 bill is $11.<br><BR>\n" );
document.write( "So the number of bills of each kind remaining is $2607/$11 = 237.<br><BR>\n" );
document.write( "ANSWERS:<BR>\n" );
document.write( "$10 bills: 237<BR>\n" );
document.write( "$1 bills: 237+293 = 530<br><BR>\n" );
document.write( "CHECK: 237(10)+530(1) = 2370+530 = 2900<br><BR>\n" );
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