document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=115081>Question 115081</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm sturggling with this problem.  Any help would be greatly appreciated.<BR>\n" );
document.write( "Solve the following non-linear system by substitution.\r<BR>\n" );
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document.write( "x^2+y^2=16<BR>\n" );
document.write( "x-2y=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83720 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83720\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x-2y=0 or x=2y<BR>\n" );
document.write( "now substitute 2y for x in the other equation & solve for y.<BR>\n" );
document.write( "(2y)^2+y^2=16<BR>\n" );
document.write( "4y^2+y^2=16<BR>\n" );
document.write( "5y^2=16<BR>\n" );
document.write( "y^2=16/5 <BR>\n" );
document.write( "y=4/sqrt5 answer.<BR>\n" );
document.write( "x-2(4/sqrt5)=0<BR>\n" );
document.write( "x-8/sqrt5=0<BR>\n" );
document.write( "x=8/sqrt5 answer.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );