document.write( "Question 1202398: A boat traveled 280 miles downstream and back. The trip downstream took 14 hours. The trip back took 140 hours. Find the speed of the boat in still water and the speed of the current. \n" ); document.write( "
Algebra.Com's Answer #837193 by mananth(16946)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let boat speed =x mph in still water
\n" ); document.write( "Let current speed =y mph
\n" ); document.write( "against current x-y time taken 140.00 hours
\n" ); document.write( "with wind x+y time taken 14.00 hours
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\n" ); document.write( "Distance = same= 140 miles
\n" ); document.write( "t=d/r \r
\n" ); document.write( "\n" ); document.write( "Upstream time equation
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\n" ); document.write( "140 / ( x - y )= 140.00 \r
\n" ); document.write( "\n" ); document.write( "Downstream time equation\r
\n" ); document.write( "\n" ); document.write( "140.00 /( x + 1 y) = 14.00 \r
\n" ); document.write( "\n" ); document.write( " x 1y = 1.00 ....................1 \r
\n" ); document.write( "\n" ); document.write( "140 / ( x- y )= 14.00
\n" ); document.write( "140 /( x - 1 y) = 14.00 \r
\n" ); document.write( "\n" ); document.write( " x - y = 10.00 ...............2 \r
\n" ); document.write( "\n" ); document.write( "Multiply (1) by 1.00
\n" ); document.write( "Multiply (2) by 1.00
\n" ); document.write( "we get
\n" ); document.write( " x + y = 1
\n" ); document.write( "x - y = 10
\n" ); document.write( "2 x = 11
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\n" ); document.write( "/ 2
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\n" ); document.write( "x = 5.5 mph
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\n" ); document.write( "plug value of x in (1)
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\n" ); document.write( "x - y = 1
\n" ); document.write( "5.5 - y = 1.00
\n" ); document.write( "-y = 1.00 -5.5
\n" ); document.write( "-1 y = -4.50
\n" ); document.write( " y = 4.5 mph \r
\n" ); document.write( "\n" ); document.write( "Complete by writing the answer
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