document.write( "Question 1202393: Twelve years ago, the age of the father was three times the age of his daughter. After twelve years, father’s age will be twice than of his daughter. The ratio present ages is? \n" ); document.write( "
Algebra.Com's Answer #837185 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Twelve years ago, the age of the father was three times the age of his daughter.\r \n" ); document.write( "\n" ); document.write( "12 years ago daughter's age be x years \n" ); document.write( "father's age = 3x\r \n" ); document.write( "\n" ); document.write( " After twelve years, father’s age will be twice than of his daughter. The ratio present ages is?\r \n" ); document.write( "\n" ); document.write( "after(12+12)= 24 years \r \n" ); document.write( "\n" ); document.write( "3x+24= 2(x+24) \n" ); document.write( "3x+24= 2x+48\r \n" ); document.write( "\n" ); document.write( "3x-2x= 48-24\r \n" ); document.write( "\n" ); document.write( "x =24 \n" ); document.write( "Present age of daughter = 24+12 =36 years. \n" ); document.write( "Father;s age = 72+12 = 84\r \n" ); document.write( "\n" ); document.write( "Ratio = 36/84 = 3/7\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |