document.write( "Question 1202338: At first there were 17 boring beetles. The number of boring beetles doubled every day.\r
\n" ); document.write( "\n" ); document.write( "(a) Write an equation that describes the number of beetles there would be after n days.\r
\n" ); document.write( "\n" ); document.write( "(b) Using the equation in (a), determine the number of beetles there would be after 30 days.
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Algebra.Com's Answer #837092 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Answers:
\n" ); document.write( "(a) P = 17*2^n
\n" ); document.write( "(b) 18,253,611,008 (roughly 18.25 billion)\r
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\n" ); document.write( "Explanation for Part (a)\r
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\n" ); document.write( "\n" ); document.write( "One possible exponential equation template is P = a*b^n
\n" ); document.write( "where,
\n" ); document.write( "n = number of days
\n" ); document.write( "P = number of beetles
\n" ); document.write( "a = starting amount
\n" ); document.write( "b = growth rate when b > 1\r
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\n" ); document.write( "\n" ); document.write( "In this case,
\n" ); document.write( "a = 17
\n" ); document.write( "b = 2, meaning the population doubles each time n goes up by 1.\r
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\n" ); document.write( "\n" ); document.write( "We go from P = a*b^n to P = 17*2^n\r
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\n" ); document.write( "\n" ); document.write( "If n = 0, then P = 17
\n" ); document.write( "If n = 1, then P = 34
\n" ); document.write( "If n = 2, then P = 68
\n" ); document.write( "and so on.\r
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\n" ); document.write( "Explanation for Part (b)\r
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\n" ); document.write( "\n" ); document.write( "Plug n = 30 into the equation we just found.
\n" ); document.write( "P = 17*2^n
\n" ); document.write( "P = 17*2^30
\n" ); document.write( "P = 18,253,611,008
\n" ); document.write( "This population count is roughly 18.25 billion.\r
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\n" ); document.write( "\n" ); document.write( "I don't know much about beetles, or insects, to know if this population count is realistic or not.
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