document.write( "Question 1202331: Ten years ago Linda was three times christys age then. Ten years from now christys age will be 4/7 of Linda’s age then. How old are they now. \n" ); document.write( "

Algebra.Com's Answer #837075 by ikleyn(52803) $\"\"$ $\"About$

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\n" ); document.write( "Ten years ago Linda was three times Christy's age then. Ten years from now
\n" ); document.write( "Christy's age will be 4/7 of Linda’s age then. How old are they now.
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\n" ); document.write( "\n" ); document.write( " I read, interpret and solve the problem in different way;\r
\n" ); document.write( "\n" ); document.write( " so my numbers are different from that of @mananth.\r
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document.write( "Let x years be the Christy's age 10 years ago;\r\n" );
document.write( "then Linda's age at that time was 3x years.\r\n" );
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document.write( "Ten years from now Christy's age will be  (x+20) years;\r\n" );
document.write( "                   Linda's   age will be (3x+20) years then.\r\n" );
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document.write( "So, I write equation as the problem states\r\n" );
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document.write( "    x + 20 = .\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    7x + 140 = 12x + 80\r\n" );
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document.write( "    140 - 80 = 12x - 7x\r\n" );
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document.write( "       60    =    5x\r\n" );
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document.write( "        x    =    60/5 = 12.\r\n" );
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document.write( "ANSWER.  Christy's age now is 12+10 = 22 years.  Linda's age now is 3*12+10 = 46 years.\r\n" );
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document.write( "CHECK.   You may check it on your own that the condition of the problem \r\n" );
document.write( "         \"in ten years\" is satisfied.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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