document.write( "Question 1202331: Ten years ago Linda was three times christys age then. Ten years from now christys age will be 4/7 of Linda’s age then. How old are they now. \n" ); document.write( "

Algebra.Com's Answer #837071 by mananth(16946) $\"\"$ $\"About$

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Ten years ago Linda was three times christys age then. Ten years from now christys age will be 4/7 of Linda’s age then. How old are they now.\r
\n" ); document.write( "\n" ); document.write( "let christy's age 10 years ago be x
\n" ); document.write( "Linda's age was 3x\r
\n" ); document.write( "\n" ); document.write( "Ten years hence
\n" ); document.write( "Christy will be x+20 years\r
\n" ); document.write( "\n" ); document.write( "Linda'sage will be 3x +20\r
\n" ); document.write( "\n" ); document.write( "x+20 = 4/7 *3x\r
\n" ); document.write( "\n" ); document.write( "7(x+20) = 12x\r
\n" ); document.write( "\n" ); document.write( "7x+140 = 12x\r
\n" ); document.write( "\n" ); document.write( "5x = 140
\n" ); document.write( "x = 28 ( christy's age 10 years ago)\r
\n" ); document.write( "\n" ); document.write( "So Christy is 28 + 10 = 38 years\r
\n" ); document.write( "\n" ); document.write( "Plug x=28\r
\n" ); document.write( "\n" ); document.write( "Linda is 3x+10 = 84+20 =94 years\r
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