document.write( "Question 1202329: If Z has a mean of 0 and a standard deviation of 1, determine the probability,\r
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document.write( "P(|Z| <2.0)\r
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document.write( "the answer is 0.9544 but i have no idea how they got that. \n" );
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Algebra.Com's Answer #837070 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "You can use a stats calculator such as a TI84 \n" ); document.write( "https://www.statology.org/normal-probabilities-ti-84-calculator/ \n" ); document.write( "or spreadsheet software \n" ); document.write( "https://www.statology.org/normalcdf-in-excel/ \n" ); document.write( "or something like this \n" ); document.write( "https://davidmlane.com/normal.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "However, I'll be using a table instead. \n" ); document.write( "This is the table I'll be using: \n" ); document.write( "https://www.ztable.net/ \n" ); document.write( "A similar table is found in the back of any stats textbook.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use that table to determine these two approximations: \n" ); document.write( "P(Z < -2.00) = 0.02275 \n" ); document.write( "P(Z < 2.00) = 0.97725\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then we can compute the following. \n" ); document.write( "P(a < Z < b) = P(Z < b) - P(Z < a) \n" ); document.write( "P(-2 < Z < 2) = P(Z < 2) - P(Z < -2) \n" ); document.write( "P(-2 < Z < 2) = 0.97725 - 0.02275 \n" ); document.write( "P(-2 < Z < 2) = 0.9545 \n" ); document.write( "P(|Z| < 2) = 0.9545\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is the approximate area under the Z curve between z = -2 and z = 2 \n" ); document.write( "The third link I mentioned at the top will draw out the diagram I'm describing. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The result 0.9545 is a bit off compared to 0.9544, but I think it's close enough. \n" ); document.write( "This slight discrepancy is due to rounding error. \n" ); document.write( " \n" ); document.write( " |