document.write( "Question 1202329: If Z has a mean of 0 and a standard deviation of 1, determine the probability,\r
\n" ); document.write( "\n" ); document.write( "P(|Z| <2.0)\r
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\n" ); document.write( "\n" ); document.write( "the answer is 0.9544 but i have no idea how they got that.
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Algebra.Com's Answer #837070 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "You can use a stats calculator such as a TI84
\n" ); document.write( "https://www.statology.org/normal-probabilities-ti-84-calculator/
\n" ); document.write( "or spreadsheet software
\n" ); document.write( "https://www.statology.org/normalcdf-in-excel/
\n" ); document.write( "or something like this
\n" ); document.write( "https://davidmlane.com/normal.html\r
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\n" ); document.write( "\n" ); document.write( "However, I'll be using a table instead.
\n" ); document.write( "This is the table I'll be using:
\n" ); document.write( "https://www.ztable.net/
\n" ); document.write( "A similar table is found in the back of any stats textbook.\r
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\n" ); document.write( "\n" ); document.write( "Use that table to determine these two approximations:
\n" ); document.write( "P(Z < -2.00) = 0.02275
\n" ); document.write( "P(Z < 2.00) = 0.97725\r
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\n" ); document.write( "\n" ); document.write( "Then we can compute the following.
\n" ); document.write( "P(a < Z < b) = P(Z < b) - P(Z < a)
\n" ); document.write( "P(-2 < Z < 2) = P(Z < 2) - P(Z < -2)
\n" ); document.write( "P(-2 < Z < 2) = 0.97725 - 0.02275
\n" ); document.write( "P(-2 < Z < 2) = 0.9545
\n" ); document.write( "P(|Z| < 2) = 0.9545\r
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\n" ); document.write( "\n" ); document.write( "This is the approximate area under the Z curve between z = -2 and z = 2
\n" ); document.write( "The third link I mentioned at the top will draw out the diagram I'm describing. \r
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\n" ); document.write( "\n" ); document.write( "The result 0.9545 is a bit off compared to 0.9544, but I think it's close enough.
\n" ); document.write( "This slight discrepancy is due to rounding error.
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