document.write( "Question 1202307: A popular soft drink is sold in 2.5-litre (i.e., 2,500 millilitres) bottles. Due to variations in
\n" ); document.write( "the production process, bottles have a mean of 2,500 millilitres and a standard deviation of
\n" ); document.write( "22, normally distributed.
\n" ); document.write( "(a) If the process fills bottles by more than 25 millilitres, the overflow will cause the machine
\n" ); document.write( "to overflow. What is the probability of this occurring?
\n" ); document.write( "(b) What is the probability of underfilling bottles by at least 15 millilitres?
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Algebra.Com's Answer #837037 by Theo(13342)\"\" \"About 
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mean is 2500.
\n" ); document.write( "standard deviation is 22.\r
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\n" ); document.write( "\n" ); document.write( "(a) If the process fills bottles by more than 25 millilitres, the overflow will cause the machine
\n" ); document.write( "to overflow. What is the probability of this occurring?\r
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\n" ); document.write( "\n" ); document.write( "i think what the probllem is saying is that the overflow will occur when the bottle is filled to more than 2525 millilitres.
\n" ); document.write( "that would be 25 millilitres more than the mean of 2500.
\n" ); document.write( "the z-score woulld be equal to (2525 - 2500) / 22 = 25 / 22 = 1.136363636.
\n" ); document.write( "the probability of that occurring would be equal to .1279022539.
\n" ); document.write( "that's the areaa to the right of that z-score.
\n" ); document.write( "that means that the probability of getting a z-score greater than that is 1.126363636.\r
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\n" ); document.write( "\n" ); document.write( "(b) What is the probability of underfilling bottles by at least 15 millilitres?\r
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\n" ); document.write( "\n" ); document.write( "the z-score would be equal to (2485 - 2500) / 22 = -15 / 22 = -.6818181818.
\n" ); document.write( "the probbility of that occurring would be equal to .2476768904.
\n" ); document.write( "that's the area to the left of that z-score.
\n" ); document.write( "that means that the probability of getting a z-score less than that is .2476768904.\r
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\n" ); document.write( "\n" ); document.write( "the calculator at < rel=nofollow HREF= \"https://www.hackmath.net/en/calculator/normal-distribution\" target = \"_blank\">https://www.hackmath.net/en/calculator/normal-distribution can be used to verify these results.\r
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\n" ); document.write( "\n" ); document.write( "here are the results from this calculator.\r
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\n" ); document.write( "\n" ); document.write( "the calculator can be used with z-scores or raw scores.
\n" ); document.write( "if z-scores, the mean is 0 and the standard deviation is 1.
\n" ); document.write( "otherwise, use the mean and standard deviation given.
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