document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1124153>Question 1124153</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given that the first term of an Arithmetical Progression is 7 and its 10th term is twice the second term. (a) calculate the 19th term.(b) sum of 28th terms (c) difference between the 9th and 6th terms </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #837014 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=837014\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given that the first term of an Arithmetical Progression is 7 and its 10th term is twice the second term. (a) calculate the 19th term.(b) sum of 28th terms (c) difference between the 9th and 6th term\r<BR>\n" );
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document.write( "a= 7\r<BR>\n" );
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document.write( "a10 = a+9d\r<BR>\n" );
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document.write( "2nd term\r<BR>\n" );
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document.write( "a2= a+d\r<BR>\n" );
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document.write( "a+9d= 2(a+d)\r<BR>\n" );
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document.write( "7+9d = 14+2d<BR>\n" );
document.write( "7d =7<BR>\n" );
document.write( "d=1\r<BR>\n" );
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document.write( "a19=  a+18d\r<BR>\n" );
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document.write( "a19= 25\r<BR>\n" );
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document.write( "S28 = 28/2(2*7+27)\r<BR>\n" );
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document.write( "=14*41=574\r<BR>\n" );
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document.write( " </SPAN>\n" );
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