document.write( "Question 1202281: Homer drove as fast as he could to get 60 miles ahead of Mae. If Homer drove at 17 miles per hour and accomplished his goal 20 hours after they both began, how fast did Mae drive? \n" ); document.write( "
Algebra.Com's Answer #837001 by Theo(13342)\"\" \"About 
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r * t = d
\n" ); document.write( "r is the rate
\n" ); document.write( "t is the time
\n" ); document.write( "d is the distance.
\n" ); document.write( "for homer:
\n" ); document.write( "17 * 20 = d + 60
\n" ); document.write( "for mae:
\n" ); document.write( "r * 20 = d
\n" ); document.write( "solve for d in homer equation to get d = 17 * 20 - 60 = 280.
\n" ); document.write( "solve for r in mae equation to get r * 20 = 280 resulting in r = 14.
\n" ); document.write( "mae was driving at 14 miles per hour should be your solution.
\n" ); document.write( "confirm by replacing r with 14 in mae's equation and by replacing d with 280 in both equations to get:
\n" ); document.write( "17 * 20 = 280 + 60 resulting in 340 = 340 in homer equation.
\n" ); document.write( "14 * 20 = 280 resulting in 280 = 280 in mae eqution.
\n" ); document.write( "homer drove 340 miles in 20 hours.
\n" ); document.write( "mae drive 280 miles in 20 hours.
\n" ); document.write( "homer drove 60 more miles than mae in the same time.
\n" ); document.write( "solution is mae drove at 14 miles per hour.\r
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