document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1185557>Question 1185557</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At point A due east to the hut the angle of elevation is 45 degree and at point B due west to the hut the angle of elevation is 30 degree. If the distance of AB is 10 meter then find the height of hut? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #836983 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=836983\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In triangle ACB angle B = 45 deg\r<BR>\n" );
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document.write( "tan 45 = 1 therefore AC =x\r<BR>\n" );
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document.write( "In triangle ADC   angle D =60 deg\r<BR>\n" );
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document.write( "x/(10-x) = tan 60 <BR>\n" );
document.write( "x = 10*tan60 - tan 60 *x\r<BR>\n" );
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document.write( "x+tan 60x = 17.32\r<BR>\n" );
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document.write( "x(1+tan 60)= 17.32\r<BR>\n" );
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document.write( "x =  17.32/ (1+tan 60)\r<BR>\n" );
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document.write( "x = 6.34  m\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/display-illustration.mpl?tutor=mananth&illustration_name=hut.png\">.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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