document.write( "Question 115062: Find the domain of f, the roots of f(x)=0, and determine the signs of f where\r
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\n" ); document.write( "\n" ); document.write( "f(x)= x^2-1/sqrt x+1 + sqrt x+1
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Algebra.Com's Answer #83696 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29=%28x%5E2-1%29%2F%28sqrt%28x%2B1%29%2Bsqrt%28x%2B1%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "This function is undefined if \"x%2B1%3C=0\", or putting a positive spin on the statement, the function is defined if and only if \"x%2B1%3E0\" => \"x%3E-1\". Therefore, the domain of the function is the interval (-1,\"infinity\"]\r
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\n" ); document.write( "\n" ); document.write( "The zeros of the function can be seen readily if you factor the numerator and then rationalize the denominator.\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28%28x%2B1%29%28x-1%29%29%2F2sqrt%28x%2B1%29\"
\n" ); document.write( "\"f%28x%29=%28%28x%2B1%29%28x-1%29sqrt%28x%2B1%29%29%2F2sqrt%28x%2B1%29sqrt%28x%2B1%29\"
\n" ); document.write( "\"f%28x%29=%28%28x%2B1%29%28x-1%29sqrt%28x%2B1%29%29%2F%282x%2B2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=0\" iff \"x-1=0\" or \"x%2B1=0\" or \"sqrt%28x%2B1%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x-1=0\" iff \"x=1\", so \"f%281%29+=+0\" and 1 is a zero of the function.
\n" ); document.write( "\"x%2B1=0\" iff \"x=-1\", but -1 is not in the domain of the function, therefore \"f%28-1%29\" is undefined (notice the open ended domain interval) and -1 is not a zero of the function.
\n" ); document.write( "\"sqrt%28x%2B1%29=0\" iff \"x%2B1=0\" => \"x=-1\", and again, -1 is not in the domain.\r
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\n" ); document.write( "\n" ); document.write( "Therefore the only zero of the function is 1.\r
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\n" ); document.write( "\n" ); document.write( "As to the balance of your question, \"determine the signs of f where...\" Where what? Re-post with the complete question and someone will try to answer.
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