document.write( "Question 115070: radical 6000 \n" ); document.write( "
Algebra.Com's Answer #83693 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%286000%29\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "The goal of simplifying expressions with square roots is to factor the radicand into a product of two numbers. One of these two numbers must be a perfect square. When you take the square root of this perfect square, you will get a rational number.\r
\n" ); document.write( "\n" ); document.write( "So let's list the factors of 6000\r
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\n" ); document.write( "\n" ); document.write( "1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 25, 30, 40, 48, 50, 60, 75, 80, 100, 120, 125, 150, 200, 240, 250, 300, 375, 400, 500, 600, 750, 1000, 1200, 1500, 2000, 3000, 6000\r
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\n" ); document.write( "\n" ); document.write( "Notice how 400 is the largest perfect square, so lets factor 6000 into 400*15\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28400%2A15%29\" Factor 6000 into 400*15
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\n" ); document.write( "\"sqrt%28400%29%2Asqrt%2815%29\" Break up the square roots using the identity \"sqrt%28x%2Ay%29=sqrt%28x%29%2Asqrt%28y%29\"
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\n" ); document.write( "\"20%2Asqrt%2815%29\" Take the square root of the perfect square 400 to get 20
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\n" ); document.write( "So the expression \"sqrt%286000%29\" simplifies to \"20%2Asqrt%2815%29\"\r
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\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "Notice if we evaluate the square root of 6000 with a calculator we get\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%286000%29=77.4596669241483\"\r
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\n" ); document.write( "\n" ); document.write( "and if we evaluate \"20%2Asqrt%2815%29\" we get\r
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\n" ); document.write( "\n" ); document.write( "\"20%2Asqrt%2815%29=77.4596669241483\"\r
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\n" ); document.write( "\n" ); document.write( "This shows that \"sqrt%286000%29=20%2Asqrt%2815%29\". So this verifies our answer
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