document.write( "Question 115061: state the domain for the function\r
\n" ); document.write( "\n" ); document.write( "y=f(x)=(sqrtx^2-9)
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Algebra.Com's Answer #83688 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Since you cannot take the square root of a negative number, set the inner expression greater than zero\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-9%3E0\"\r
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\n" ); document.write( "\n" ); document.write( "Now if you graph \"x%5E2-9\"\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2-9%29+\"\r
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\n" ); document.write( "\n" ); document.write( "we can see that the graph is greater than zero when \"x%3C-3\" or \"x%3E3\"\r
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\n" ); document.write( "\n" ); document.write( "So the domain of \"f%28x%29=sqrt%28x%5E2-9%29\" is \r
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