document.write( "Question 1202206: Find three consecutive integers such that -7 times the sum of the first and third is 12 greater than the product of 10 and the opposite of the second. \n" ); document.write( "
Algebra.Com's Answer #836871 by mananth(16946)\"\" \"About 
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\n" ); document.write( "Find three consecutive integers such that -7 times the sum of the first and third is 12 greater than the product of 10 and the opposite of the second.
\n" ); document.write( "let the integers be x,x+1,x+2\r
\n" ); document.write( "\n" ); document.write( "-7*(x+x+2) = 10*-(x+1)+12\r
\n" ); document.write( "\n" ); document.write( "-7(2x+2) = -10x-10+12\r
\n" ); document.write( "\n" ); document.write( "-14x-14 = -10x+2\r
\n" ); document.write( "\n" ); document.write( "4x=-16
\n" ); document.write( "x=-4\r
\n" ); document.write( "\n" ); document.write( "The integers are -4, -3,-2\r
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