document.write( "Question 1202194: The area of a rectangle is 45m^2, and the length of the rectangle is 1m more than twice the width. Find the dimensions of the rectangle.
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Algebra.Com's Answer #836846 by Theo(13342)\"\" \"About 
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area of rectangle = 45 square meters.
\n" ); document.write( "the length of the rectangle is 1 meter more than twice the width.
\n" ); document.write( "L = length
\n" ); document.write( "W = width
\n" ); document.write( "L = 2W + 1
\n" ); document.write( "A = area = 45
\n" ); document.write( "A = L * W
\n" ); document.write( "replace L with 2W + 1 to get:
\n" ); document.write( "A = (2W + 1) * W
\n" ); document.write( "simplify to get:
\n" ); document.write( "A = 2W^2 + W
\n" ); document.write( "since A = 45, equation becomes:
\n" ); document.write( "45 = 2W^2 + W
\n" ); document.write( "subtract 45 from both sides of the equation to get:
\n" ); document.write( "2W^2 + W - 45 = 0
\n" ); document.write( "factor to get:
\n" ); document.write( "(2W + 10) * (W - 4.5) = 0
\n" ); document.write( "solve for W to get:
\n" ); document.write( "W = -10 or W = 4.5
\n" ); document.write( "W can't be negative, so W = 4.5
\n" ); document.write( "since A = 45 and W = 4.5, then L has to be equal to 10.
\n" ); document.write( "L = 2W + 1 becomes 10 = 2*4.5 + 1 which becomes 10 = 10, confirming the relationship between L and W is correct.
\n" ); document.write( "solution is that the dimensions of the rectangle are 10 by 4.5
\n" ); document.write( "10 is the length.
\n" ); document.write( "4.5 is the width. \n" ); document.write( "
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